Pass4Test est un bon site qui provide la façon efficace à se former à court terme pour réussir le test Microsoft 70-457, c'est un certificat qui peut améliorer le niveau de vie. Les gens avec le Certificat gagent beaucoup plus que les gens sans Certificat Microsoft 70-457. Vous aurez une space plus grande à se développer.
70-457 est un test de Microsoft Certification, donc réussir 70-457 est le premier pas à mettre le pied sur la Certifiction Microsoft. Ça peut expliquer certiainement pourquoi le test Microsoft 70-457 devient de plus en plus chaud, et il y a de plus en plus de gens qui veulent participer le test 70-457. Au contraire, il n'y a que pas beaucoup de gens qui pourrait réussir ce test. Dans ce cas, si vous vous réfléchissez étudier avec une bonne Q&A?
Pass4Test est aussi un site d'offrir la ressource des connaissances pour le test Certification IT. Selon les Feedbacks venus de gens qui ont untilié les produits de Pass4Test, Pass4Test est un site fiable comme l'outil de se former. Les Q&As offertes par Pass4Test sont bien précises. Les experts de Pass4Test mettent à jour nos documentations de formation de temps de temps.
Code d'Examen: 70-457
Nom d'Examen: Microsoft (Transition Your MCTS on SQL Server 2008 to MCSA: SQL Server 2012, Part 1)
Questions et réponses: 172 Q&As
Le test Microsoft 70-457 est l'un très improtant dans tous les tests de Certification Microsoft, mais c'est toujours difficile à obtenir ce Certificat. La présence de Pass4Test est pour soulager les candidats. L'équipe de Pass4Test peut vous aider à économiser le temps et l'éffort. Vous pouvez passer le test sans aucune doute sous l'aide de notre Q&A.
Est-ce que vous vous souciez encore pour passer le test Microsoft 70-457? Pourquoi pas choisir la formation en Internet dans une société de l'informatique. Un bon choix de l'outil formation peut résoudre le problème de prendre grande quantité de connaissances demandées par le test Microsoft 70-457, et vous permet de préparer mieux avant le test. Les experts de Pass4Test travaillent avec tous efforts à produire une bonne Q&A ciblée au test Microsoft 70-457. La Q&A est un bon choix pour vous. Vous pouvez télécharger le démo grantuit tout d'abord en Internet.
Pass4Test est un bon catalyseur du succès pour les professionnels IT. Beaucoup de gens passer le test Microsoft 70-457 avec l'aide de l'outil formation. Les experts profitent leurs expériences riches et connaissances à faire sortir la Q&A Microsoft 70-457 plus nouvelle qui comprend les exercices de pratiquer et le test simulation. Vous pouvez passer le test Microsoft 70-457 plus facilement avec la Q&A de Pass4Test.
Vous Microsoft 70-457 pouvez télécharger le démo Microsoft 70-457 gratuit dans le site Pass4Test pour essayer notre qualité. Une fois vous achetez le produit de Pass4Test, nous allons faire tous effort à vous aider à réussir le test à la première fois et vous laisser savoir qu'il ne faut pas beaucoup de travaux pour réussir ce que vous voulez.
70-457 Démo gratuit à télécharger: http://www.pass4test.fr/70-457.html
NO.1 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure
that the following requirements are met:
. Students must be ranked based on their average marks.
. If one or more students have the same average, incremental ranks must be given based on the order
they are created.
. Ranks must be sequential without gaps in between.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code, RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: C
Microsoft examen 70-457 certification 70-457
NO.2 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects. You need to ensure
that the top half of the students arranged by their average marks must be given a rank of 1 and the
remaining students must be given a rank of 2.
Which Transact-SQL query should you use?
A. SELECT StudentCode as Code,
RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code,
DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode as Code,
NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value
FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM
(SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: D
Microsoft 70-457 certification 70-457 70-457 70-457 examen
NO.3 You are developing a database application by using Microsoft SQL Server 2012. You have a query that
runs slower than expected. You need to capture execution plans that will include detailed information on
missing indexes recommended by the query optimizer.
What should you do?
A. Add a HASH hint to the query.
B. Add a LOOP hint to the query.
C. Add a FORCESEEK hint to the query.
D. Add an INCLUDE clause to the index.
E. Add a FORCESCAN hint to the Attach query.
F. Add a columnstore index to cover the query.
G. Enable the optimize for ad hoc workloads option.
H. Cover the unique clustered index with a columnstore index.
I. Include a SET FORCEPLAN ON statement before you run the query.
J. Include a SET STATISTICS PROFILE ON statement before you run the query.
K. Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
L. Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the
query.
M. Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
N. Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the
query.
Answer: K
Microsoft 70-457 examen 70-457
NO.4 You are developing a database application by using Microsoft SQL Server 2012. An application that
uses a database begins to run slowly. Your investigation shows the root cause is a query against a
read-only table that has a clustered index.
The query returns the following six columns:
. One column in its WHERE clause contained in a non-clustered index
. Four additional columns
. One COUNT (*) column based on a grouping of the four additional columns
You need to optimize the statement. What should you do?
A. Add a HASH hint to the query.
B. Add a LOOP hint to the query.
C. Add a FORCESEEK hint to the query.
D. Add an INCLUDE clause to the index.
E. Add a FORCESCAN hint to the Attach query.
F. Add a columnstore index to cover the query.
G. Enable the optimize for ad hoc workloads option.
H. Cover the unique clustered index with a columnstore index.
I. Include a SET FORCEPLAN ON statement before you run the query.
J. Include a SET STATISTICS PROFILE ON statement before you run the query.
K. Include a SET STATISTICS SHOWPLAN_XML ON statement before you run the query.
L. Include a SET TRANSACTION ISOLATION LEVEL REPEATABLE READ statement before you run the
query.
M. Include a SET TRANSACTION ISOLATION LEVEL SNAPSHOT statement before you run the query.
N. Include a SET TRANSACTION ISOLATION LEVEL SERIALIZABLE statement before you run the
query.
Answer: F
certification Microsoft certification 70-457 70-457
NO.5 You create a table that has the StudentCode, SubjectCode, and Marks columns to record mid-year
marks for students. The table has marks obtained by 50 students for various subjects.
You need to ensure that the following requirements are met:
. Students must be ranked based on their average marks.
. If one or more students have the same average, the same rank must be given to these students.
. Consecutive ranks must be skipped when the same rank is assigned.
Which Transact-SQL query should you use.?
A. SELECT StudentCode as Code, RANK ( ) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
B. SELECT Id, Name, Marks, DENSE_RANK () OVER (ORDER BY Marks DESC) AS Rank FROM
StudentMarks
C. SELECT StudentCode as Code, DENSE_RANK () OVER (ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks GROUP BY StudentCode
D. SELECT StudentCode as Code, NTILE (2) OVER (ORDER BY AVG (Marks) DESC) AS Value FROM
StudentMarks GROUP BY StudentCode
E. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
F. SELECT StudentCode AS Code,Marks AS Value FRCM ( SELECT StudentCode, Marks AS Marks,
RANK() OVER (PARTITION BY SubjectCode ORDER 3Y Marks DESC) AS Rank FRCM StudentMarks)
tmp WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
H. SELECT StudentCode AS Code,Marks AS Value FROM (SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank FROM StudentMarks)
tmp WHERE Rank = 1
Answer: A
certification Microsoft 70-457 examen 70-457 70-457 examen
Le test Certification Microsoft 70-457 est une chance précieuse à augmenter vos connaissances de technologie informatique dans l'industrie IT. Il attire beaucoup de professionls à participer ce test. Pass4Test peut vous offrir les outils de formation particuliers à propos de test Microsoft 70-457. Vous réaliserez plus tôt votre rêve avec la Q&A écrite par l'équipe professionnelle de Pass4Test. Pass4Test se contribue à vous donner un coup de main pour réussir le test Microsoft 70-457.
没有评论:
发表评论